Optimal. Leaf size=326 \[ \frac{\sqrt [4]{a} \left (\sqrt{a}+\sqrt{c} x^2\right ) \sqrt{\frac{a+c x^4}{\left (\sqrt{a}+\sqrt{c} x^2\right )^2}} \left (\frac{5 \sqrt{c} d \left (c d^2-a e^2\right )}{\sqrt{a}}-3 a e^3+15 c d^2 e\right ) \text{EllipticF}\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} x}{\sqrt [4]{a}}\right ),\frac{1}{2}\right )}{10 c^{7/4} \sqrt{a+c x^4}}+\frac{3 e x \sqrt{a+c x^4} \left (5 c d^2-a e^2\right )}{5 c^{3/2} \left (\sqrt{a}+\sqrt{c} x^2\right )}-\frac{3 \sqrt [4]{a} e \left (\sqrt{a}+\sqrt{c} x^2\right ) \sqrt{\frac{a+c x^4}{\left (\sqrt{a}+\sqrt{c} x^2\right )^2}} \left (5 c d^2-a e^2\right ) E\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{5 c^{7/4} \sqrt{a+c x^4}}+\frac{d e^2 x \sqrt{a+c x^4}}{c}+\frac{e^3 x^3 \sqrt{a+c x^4}}{5 c} \]
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Rubi [A] time = 0.286931, antiderivative size = 326, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 5, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.238, Rules used = {1207, 1888, 1198, 220, 1196} \[ \frac{3 e x \sqrt{a+c x^4} \left (5 c d^2-a e^2\right )}{5 c^{3/2} \left (\sqrt{a}+\sqrt{c} x^2\right )}+\frac{\sqrt [4]{a} \left (\sqrt{a}+\sqrt{c} x^2\right ) \sqrt{\frac{a+c x^4}{\left (\sqrt{a}+\sqrt{c} x^2\right )^2}} \left (\frac{5 \sqrt{c} d \left (c d^2-a e^2\right )}{\sqrt{a}}-3 a e^3+15 c d^2 e\right ) F\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{10 c^{7/4} \sqrt{a+c x^4}}-\frac{3 \sqrt [4]{a} e \left (\sqrt{a}+\sqrt{c} x^2\right ) \sqrt{\frac{a+c x^4}{\left (\sqrt{a}+\sqrt{c} x^2\right )^2}} \left (5 c d^2-a e^2\right ) E\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{5 c^{7/4} \sqrt{a+c x^4}}+\frac{d e^2 x \sqrt{a+c x^4}}{c}+\frac{e^3 x^3 \sqrt{a+c x^4}}{5 c} \]
Antiderivative was successfully verified.
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Rule 1207
Rule 1888
Rule 1198
Rule 220
Rule 1196
Rubi steps
\begin{align*} \int \frac{\left (d+e x^2\right )^3}{\sqrt{a+c x^4}} \, dx &=\frac{e^3 x^3 \sqrt{a+c x^4}}{5 c}+\frac{\int \frac{5 c d^3+3 e \left (5 c d^2-a e^2\right ) x^2+15 c d e^2 x^4}{\sqrt{a+c x^4}} \, dx}{5 c}\\ &=\frac{d e^2 x \sqrt{a+c x^4}}{c}+\frac{e^3 x^3 \sqrt{a+c x^4}}{5 c}+\frac{\int \frac{15 c d \left (c d^2-a e^2\right )+9 c e \left (5 c d^2-a e^2\right ) x^2}{\sqrt{a+c x^4}} \, dx}{15 c^2}\\ &=\frac{d e^2 x \sqrt{a+c x^4}}{c}+\frac{e^3 x^3 \sqrt{a+c x^4}}{5 c}-\frac{\left (3 \sqrt{a} e \left (5 c d^2-a e^2\right )\right ) \int \frac{1-\frac{\sqrt{c} x^2}{\sqrt{a}}}{\sqrt{a+c x^4}} \, dx}{5 c^{3/2}}+\frac{\left (5 \sqrt{c} d \left (c d^2-a e^2\right )+3 \sqrt{a} e \left (5 c d^2-a e^2\right )\right ) \int \frac{1}{\sqrt{a+c x^4}} \, dx}{5 c^{3/2}}\\ &=\frac{d e^2 x \sqrt{a+c x^4}}{c}+\frac{e^3 x^3 \sqrt{a+c x^4}}{5 c}+\frac{3 e \left (5 c d^2-a e^2\right ) x \sqrt{a+c x^4}}{5 c^{3/2} \left (\sqrt{a}+\sqrt{c} x^2\right )}-\frac{3 \sqrt [4]{a} e \left (5 c d^2-a e^2\right ) \left (\sqrt{a}+\sqrt{c} x^2\right ) \sqrt{\frac{a+c x^4}{\left (\sqrt{a}+\sqrt{c} x^2\right )^2}} E\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{5 c^{7/4} \sqrt{a+c x^4}}+\frac{\left (5 \sqrt{c} d \left (c d^2-a e^2\right )+3 \sqrt{a} e \left (5 c d^2-a e^2\right )\right ) \left (\sqrt{a}+\sqrt{c} x^2\right ) \sqrt{\frac{a+c x^4}{\left (\sqrt{a}+\sqrt{c} x^2\right )^2}} F\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{10 \sqrt [4]{a} c^{7/4} \sqrt{a+c x^4}}\\ \end{align*}
Mathematica [C] time = 0.144001, size = 140, normalized size = 0.43 \[ \frac{5 d x \sqrt{\frac{c x^4}{a}+1} \left (c d^2-a e^2\right ) \, _2F_1\left (\frac{1}{4},\frac{1}{2};\frac{5}{4};-\frac{c x^4}{a}\right )+e x \left (x^2 \sqrt{\frac{c x^4}{a}+1} \left (5 c d^2-a e^2\right ) \, _2F_1\left (\frac{1}{2},\frac{3}{4};\frac{7}{4};-\frac{c x^4}{a}\right )+e \left (a+c x^4\right ) \left (5 d+e x^2\right )\right )}{5 c \sqrt{a+c x^4}} \]
Antiderivative was successfully verified.
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Maple [C] time = 0.052, size = 388, normalized size = 1.2 \begin{align*}{e}^{3} \left ({\frac{{x}^{3}}{5\,c}\sqrt{c{x}^{4}+a}}-{{\frac{3\,i}{5}}{a}^{{\frac{3}{2}}}\sqrt{1-{i{x}^{2}\sqrt{c}{\frac{1}{\sqrt{a}}}}}\sqrt{1+{i{x}^{2}\sqrt{c}{\frac{1}{\sqrt{a}}}}} \left ({\it EllipticF} \left ( x\sqrt{{i\sqrt{c}{\frac{1}{\sqrt{a}}}}},i \right ) -{\it EllipticE} \left ( x\sqrt{{i\sqrt{c}{\frac{1}{\sqrt{a}}}}},i \right ) \right ){c}^{-{\frac{3}{2}}}{\frac{1}{\sqrt{{i\sqrt{c}{\frac{1}{\sqrt{a}}}}}}}{\frac{1}{\sqrt{c{x}^{4}+a}}}} \right ) +3\,d{e}^{2} \left ( 1/3\,{\frac{x\sqrt{c{x}^{4}+a}}{c}}-1/3\,{\frac{a}{c\sqrt{c{x}^{4}+a}}\sqrt{1-{\frac{i\sqrt{c}{x}^{2}}{\sqrt{a}}}}\sqrt{1+{\frac{i\sqrt{c}{x}^{2}}{\sqrt{a}}}}{\it EllipticF} \left ( x\sqrt{{\frac{i\sqrt{c}}{\sqrt{a}}}},i \right ){\frac{1}{\sqrt{{\frac{i\sqrt{c}}{\sqrt{a}}}}}}} \right ) +{3\,i{d}^{2}e\sqrt{a}\sqrt{1-{i{x}^{2}\sqrt{c}{\frac{1}{\sqrt{a}}}}}\sqrt{1+{i{x}^{2}\sqrt{c}{\frac{1}{\sqrt{a}}}}} \left ({\it EllipticF} \left ( x\sqrt{{i\sqrt{c}{\frac{1}{\sqrt{a}}}}},i \right ) -{\it EllipticE} \left ( x\sqrt{{i\sqrt{c}{\frac{1}{\sqrt{a}}}}},i \right ) \right ){\frac{1}{\sqrt{{i\sqrt{c}{\frac{1}{\sqrt{a}}}}}}}{\frac{1}{\sqrt{c{x}^{4}+a}}}{\frac{1}{\sqrt{c}}}}+{{d}^{3}\sqrt{1-{i{x}^{2}\sqrt{c}{\frac{1}{\sqrt{a}}}}}\sqrt{1+{i{x}^{2}\sqrt{c}{\frac{1}{\sqrt{a}}}}}{\it EllipticF} \left ( x\sqrt{{i\sqrt{c}{\frac{1}{\sqrt{a}}}}},i \right ){\frac{1}{\sqrt{{i\sqrt{c}{\frac{1}{\sqrt{a}}}}}}}{\frac{1}{\sqrt{c{x}^{4}+a}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (e x^{2} + d\right )}^{3}}{\sqrt{c x^{4} + a}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{e^{3} x^{6} + 3 \, d e^{2} x^{4} + 3 \, d^{2} e x^{2} + d^{3}}{\sqrt{c x^{4} + a}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [C] time = 3.58309, size = 173, normalized size = 0.53 \begin{align*} \frac{d^{3} x \Gamma \left (\frac{1}{4}\right ){{}_{2}F_{1}\left (\begin{matrix} \frac{1}{4}, \frac{1}{2} \\ \frac{5}{4} \end{matrix}\middle |{\frac{c x^{4} e^{i \pi }}{a}} \right )}}{4 \sqrt{a} \Gamma \left (\frac{5}{4}\right )} + \frac{3 d^{2} e x^{3} \Gamma \left (\frac{3}{4}\right ){{}_{2}F_{1}\left (\begin{matrix} \frac{1}{2}, \frac{3}{4} \\ \frac{7}{4} \end{matrix}\middle |{\frac{c x^{4} e^{i \pi }}{a}} \right )}}{4 \sqrt{a} \Gamma \left (\frac{7}{4}\right )} + \frac{3 d e^{2} x^{5} \Gamma \left (\frac{5}{4}\right ){{}_{2}F_{1}\left (\begin{matrix} \frac{1}{2}, \frac{5}{4} \\ \frac{9}{4} \end{matrix}\middle |{\frac{c x^{4} e^{i \pi }}{a}} \right )}}{4 \sqrt{a} \Gamma \left (\frac{9}{4}\right )} + \frac{e^{3} x^{7} \Gamma \left (\frac{7}{4}\right ){{}_{2}F_{1}\left (\begin{matrix} \frac{1}{2}, \frac{7}{4} \\ \frac{11}{4} \end{matrix}\middle |{\frac{c x^{4} e^{i \pi }}{a}} \right )}}{4 \sqrt{a} \Gamma \left (\frac{11}{4}\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (e x^{2} + d\right )}^{3}}{\sqrt{c x^{4} + a}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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